Hi everybody,

I have a general question about how many different cases have to be

covered in one Example.

Considering the famous Fizzbuzz program, you should test if your output

is either “Fizz”, “buzz”, “Fizzbuzz” or just the number (between 1 and

100). Pretty simple. However, I often see solutions of testing multiples

of 3 only by looking at some relevant values like 6, 9 etc.

it “should return ‘fizz’ when number is divisible by 3” do

@fizzbuzz.calculate(3).should == ‘fizz’

@fizzbuzz.calculate(6).should == ‘fizz’

@fizzbuzz.calculate(9).should == ‘fizz’

end

So far, so good. But what if I claim that the test will fail in case of

12? It’s actually not covered and we are just assuming, that all further

multiples will work as well, because these do. My idea was to check all

multiples right away in a loop.

it “should return Fizz if number is divisible only by 3” do

(1…100).each do |number|

@fizzbuzz.calculate(number).should == “Fizz” if number % 3 == 0 &&

number % 5 != 0

end

end

Given that the calculate method works fine, both ways will pass. But my

question is: Does my solution more than it actually needs to or is the

first one in fact a little too lazy?

Thanks for your thoughts.

Ulfmann